3(d-7)=4(2d+1)

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Solution for 3(d-7)=4(2d+1) equation:



3(d-7)=4(2d+1)
We move all terms to the left:
3(d-7)-(4(2d+1))=0
We multiply parentheses
3d-(4(2d+1))-21=0
We calculate terms in parentheses: -(4(2d+1)), so:
4(2d+1)
We multiply parentheses
8d+4
Back to the equation:
-(8d+4)
We get rid of parentheses
3d-8d-4-21=0
We add all the numbers together, and all the variables
-5d-25=0
We move all terms containing d to the left, all other terms to the right
-5d=25
d=25/-5
d=-5

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