3(d-8)+7=6(d+2)-3d-29

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Solution for 3(d-8)+7=6(d+2)-3d-29 equation: 


Simplifying
3(d + -8) + 7 = 6(d + 2) + -3d + -29

Reorder the terms:
3(-8 + d) + 7 = 6(d + 2) + -3d + -29
(-8 * 3 + d * 3) + 7 = 6(d + 2) + -3d + -29
(-24 + 3d) + 7 = 6(d + 2) + -3d + -29

Reorder the terms:
-24 + 7 + 3d = 6(d + 2) + -3d + -29

Combine like terms: -24 + 7 = -17
-17 + 3d = 6(d + 2) + -3d + -29

Reorder the terms:
-17 + 3d = 6(2 + d) + -3d + -29
-17 + 3d = (2 * 6 + d * 6) + -3d + -29
-17 + 3d = (12 + 6d) + -3d + -29

Reorder the terms:
-17 + 3d = 12 + -29 + 6d + -3d

Combine like terms: 12 + -29 = -17
-17 + 3d = -17 + 6d + -3d

Combine like terms: 6d + -3d = 3d
-17 + 3d = -17 + 3d

Add '17' to each side of the equation.
-17 + 17 + 3d = -17 + 17 + 3d

Combine like terms: -17 + 17 = 0
0 + 3d = -17 + 17 + 3d
3d = -17 + 17 + 3d

Combine like terms: -17 + 17 = 0
3d = 0 + 3d
3d = 3d

Add '-3d' to each side of the equation.
3d + -3d = 3d + -3d

Combine like terms: 3d + -3d = 0
0 = 3d + -3d

Combine like terms: 3d + -3d = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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