3(d-8)-5=3(d+2)-35

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Solution for 3(d-8)-5=3(d+2)-35 equation: 



3(d-8)-5=3(d+2)-35

We move all terms to the left:

3(d-8)-5-(3(d+2)-35)=0

We multiply parentheses

3d-(3(d+2)-35)-24-5=0



We calculate terms in parentheses: -(3(d+2)-35), so:

3(d+2)-35

We multiply parentheses

3d+6-35

We add all the numbers together, and all the variables

3d-29

Back to the equation:

-(3d-29)



We add all the numbers together, and all the variables

3d-(3d-29)-29=0

We get rid of parentheses

3d-3d+29-29=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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