3(d-8)-5=9(2+d)+1

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Solution for 3(d-8)-5=9(2+d)+1 equation: 



3(d-8)-5=9(2+d)+1

We move all terms to the left:

3(d-8)-5-(9(2+d)+1)=0

We add all the numbers together, and all the variables

3(d-8)-(9(d+2)+1)-5=0

We multiply parentheses

3d-(9(d+2)+1)-24-5=0



We calculate terms in parentheses: -(9(d+2)+1), so:

9(d+2)+1

We multiply parentheses

9d+18+1

We add all the numbers together, and all the variables

9d+19

Back to the equation:

-(9d+19)



We add all the numbers together, and all the variables

3d-(9d+19)-29=0

We get rid of parentheses

3d-9d-19-29=0

We add all the numbers together, and all the variables

-6d-48=0

We move all terms containing d to the left, all other terms to the right

-6d=48

d=48/-6

d=-8

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