3(d-8)-5=9(s+2)+1

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Solution for 3(d-8)-5=9(s+2)+1 equation: 


Simplifying
3(d + -8) + -5 = 9(s + 2) + 1

Reorder the terms:
3(-8 + d) + -5 = 9(s + 2) + 1
(-8 * 3 + d * 3) + -5 = 9(s + 2) + 1
(-24 + 3d) + -5 = 9(s + 2) + 1

Reorder the terms:
-24 + -5 + 3d = 9(s + 2) + 1

Combine like terms: -24 + -5 = -29
-29 + 3d = 9(s + 2) + 1

Reorder the terms:
-29 + 3d = 9(2 + s) + 1
-29 + 3d = (2 * 9 + s * 9) + 1
-29 + 3d = (18 + 9s) + 1

Reorder the terms:
-29 + 3d = 18 + 1 + 9s

Combine like terms: 18 + 1 = 19
-29 + 3d = 19 + 9s

Solving
-29 + 3d = 19 + 9s

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '29' to each side of the equation.
-29 + 29 + 3d = 19 + 29 + 9s

Combine like terms: -29 + 29 = 0
0 + 3d = 19 + 29 + 9s
3d = 19 + 29 + 9s

Combine like terms: 19 + 29 = 48
3d = 48 + 9s

Divide each side by '3'.
d = 16 + 3s

Simplifying
d = 16 + 3s

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