3(d-8)-9(d+2)=6

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Solution for 3(d-8)-9(d+2)=6 equation: 



3(d-8)-9(d+2)=6

We move all terms to the left:

3(d-8)-9(d+2)-(6)=0

We multiply parentheses

3d-9d-24-18-6=0

We add all the numbers together, and all the variables

-6d-48=0

We move all terms containing d to the left, all other terms to the right

-6d=48

d=48/-6

d=-8

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