3(d-8)/4=2(d+1)/3

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Solution for 3(d-8)/4=2(d+1)/3 equation:



3(d-8)/4=2(d+1)/3
We move all terms to the left:
3(d-8)/4-(2(d+1)/3)=0
We calculate fractions
3d/()+(-(2(d+1)*4)/()=0
We calculate terms in parentheses: +(-(2(d+1)*4)/(), so:
-(2(d+1)*4)/(
We multiply all the terms by the denominator
-(2(d+1)*4)
We calculate terms in parentheses: -(2(d+1)*4), so:
2(d+1)*4
We multiply parentheses
8d+8
Back to the equation:
-(8d+8)
We get rid of parentheses
-8d-8
Back to the equation:
+(-8d-8)
We get rid of parentheses
3d/()-8d-8=0
We multiply all the terms by the denominator
3d-8d*()-8*()=0
We add all the numbers together, and all the variables
3d-8d*()=0

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