3(d=11)=6(d+33)

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Solution for 3(d=11)=6(d+33) equation:



3(d=11)=6(d+33)
We move all terms to the left:
3(d-(11))=0
We multiply parentheses
3d-33=0
We move all terms containing d to the left, all other terms to the right
3d=33
d=33/3
d=11

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