3(d=11)=6(d+33)

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Solution for 3(d=11)=6(d+33) equation: 



3(d=11)=6(d+33)

We move all terms to the left:

3(d-(11))=0

We multiply parentheses

3d-33=0

We move all terms containing d to the left, all other terms to the right

3d=33

d=33/3

d=11

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