3(e+2)=2(3e-2)

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Solution for 3(e+2)=2(3e-2) equation: 



3(e+2)=2(3e-2)

We move all terms to the left:

3(e+2)-(2(3e-2))=0

We multiply parentheses

3e-(2(3e-2))+6=0



We calculate terms in parentheses: -(2(3e-2)), so:

2(3e-2)

We multiply parentheses

6e-4

Back to the equation:

-(6e-4)



We get rid of parentheses

3e-6e+4+6=0

We add all the numbers together, and all the variables

-3e+10=0

We move all terms containing e to the left, all other terms to the right

-3e=-10

e=-10/-3

e=3+1/3

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