3(e+2)=2(3e-2)

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Solution for 3(e+2)=2(3e-2) equation:



3(e+2)=2(3e-2)
We move all terms to the left:
3(e+2)-(2(3e-2))=0
We multiply parentheses
3e-(2(3e-2))+6=0
We calculate terms in parentheses: -(2(3e-2)), so:
2(3e-2)
We multiply parentheses
6e-4
Back to the equation:
-(6e-4)
We get rid of parentheses
3e-6e+4+6=0
We add all the numbers together, and all the variables
-3e+10=0
We move all terms containing e to the left, all other terms to the right
-3e=-10
e=-10/-3
e=3+1/3

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