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3(e-1)=2+(3e-4)
We move all terms to the left:
3(e-1)-(2+(3e-4))=0
We multiply parentheses
3e-(2+(3e-4))-3=0
We calculate terms in parentheses: -(2+(3e-4)), so:We get rid of parentheses
2+(3e-4)
determiningTheFunctionDomain (3e-4)+2
We get rid of parentheses
3e-4+2
We add all the numbers together, and all the variables
3e-2
Back to the equation:
-(3e-2)
3e-3e+2-3=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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