3(e-1)=2+(3e-4)

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Solution for 3(e-1)=2+(3e-4) equation: 



3(e-1)=2+(3e-4)

We move all terms to the left:

3(e-1)-(2+(3e-4))=0

We multiply parentheses

3e-(2+(3e-4))-3=0



We calculate terms in parentheses: -(2+(3e-4)), so:

2+(3e-4)

determiningTheFunctionDomain
(3e-4)+2

We get rid of parentheses

3e-4+2

We add all the numbers together, and all the variables

3e-2

Back to the equation:

-(3e-2)



We get rid of parentheses

3e-3e+2-3=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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