3(f+1)=3(2f+1)

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Solution for 3(f+1)=3(2f+1) equation: 



3(f+1)=3(2f+1)

We move all terms to the left:

3(f+1)-(3(2f+1))=0

We multiply parentheses

3f-(3(2f+1))+3=0



We calculate terms in parentheses: -(3(2f+1)), so:

3(2f+1)

We multiply parentheses

6f+3

Back to the equation:

-(6f+3)



We get rid of parentheses

3f-6f-3+3=0

We add all the numbers together, and all the variables

-3f=0

f=0/-3

f=0

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