3(f+1)=4f+6

Solution for 3(f+1)=4f+6 equation:

Simplifying
3(f + 1) = 4f + 6

Reorder the terms:
3(1 + f) = 4f + 6
(1 * 3 + f * 3) = 4f + 6
(3 + 3f) = 4f + 6

Reorder the terms:
3 + 3f = 6 + 4f

Solving
3 + 3f = 6 + 4f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-4f' to each side of the equation.
3 + 3f + -4f = 6 + 4f + -4f

Combine like terms: 3f + -4f = -1f
3 + -1f = 6 + 4f + -4f

Combine like terms: 4f + -4f = 0
3 + -1f = 6 + 0
3 + -1f = 6

Add '-3' to each side of the equation.
3 + -3 + -1f = 6 + -3

Combine like terms: 3 + -3 = 0
0 + -1f = 6 + -3
-1f = 6 + -3

Combine like terms: 6 + -3 = 3
-1f = 3

Divide each side by '-1'.
f = -3

Simplifying
f = -3