3(f+2)+2=20

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Solution for 3(f+2)+2=20 equation: 



3(f+2)+2=20

We move all terms to the left:

3(f+2)+2-(20)=0

We add all the numbers together, and all the variables

3(f+2)-18=0

We multiply parentheses

3f+6-18=0

We add all the numbers together, and all the variables

3f-12=0

We move all terms containing f to the left, all other terms to the right

3f=12

f=12/3

f=4

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