3(f+2)+9=19=13+5f

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Solution for 3(f+2)+9=19=13+5f equation: 



3(f+2)+9=19=13+5f

We move all terms to the left:

3(f+2)+9-(19)=0

We add all the numbers together, and all the variables

3(f+2)-10=0

We multiply parentheses

3f+6-10=0

We add all the numbers together, and all the variables

3f-4=0

We move all terms containing f to the left, all other terms to the right

3f=4

f=4/3

f=1+1/3

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