3(f+2)-4f=5(f-1)-(f-2)

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Solution for 3(f+2)-4f=5(f-1)-(f-2) equation: 



3(f+2)-4f=5(f-1)-(f-2)

We move all terms to the left:

3(f+2)-4f-(5(f-1)-(f-2))=0

We add all the numbers together, and all the variables

-4f+3(f+2)-(5(f-1)-(f-2))=0

We multiply parentheses

-4f+3f-(5(f-1)-(f-2))+6=0



We calculate terms in parentheses: -(5(f-1)-(f-2)), so:

5(f-1)-(f-2)

We multiply parentheses

5f-(f-2)-5

We get rid of parentheses

5f-f+2-5

We add all the numbers together, and all the variables

4f-3

Back to the equation:

-(4f-3)



We add all the numbers together, and all the variables

-1f-(4f-3)+6=0

We get rid of parentheses

-1f-4f+3+6=0

We add all the numbers together, and all the variables

-5f+9=0

We move all terms containing f to the left, all other terms to the right

-5f=-9

f=-9/-5

f=1+4/5

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