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3(f+2)-5=1+3f
We move all terms to the left:
3(f+2)-5-(1+3f)=0
We add all the numbers together, and all the variables
3(f+2)-(3f+1)-5=0
We multiply parentheses
3f-(3f+1)+6-5=0
We get rid of parentheses
3f-3f-1+6-5=0
We add all the numbers together, and all the variables
=0
f=0/1
f=0
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