3(f+2)=(2-f)

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Solution for 3(f+2)=(2-f) equation:



3(f+2)=(2-f)
We move all terms to the left:
3(f+2)-((2-f))=0
We add all the numbers together, and all the variables
3(f+2)-((-1f+2))=0
We multiply parentheses
3f-((-1f+2))+6=0
We calculate terms in parentheses: -((-1f+2)), so:
(-1f+2)
We get rid of parentheses
-1f+2
Back to the equation:
-(-1f+2)
We get rid of parentheses
3f+1f-2+6=0
We add all the numbers together, and all the variables
4f+4=0
We move all terms containing f to the left, all other terms to the right
4f=-4
f=-4/4
f=-1

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