3(f+20)+20=12(f-5)+f

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Solution for 3(f+20)+20=12(f-5)+f equation:


Simplifying
3(f + 20) + 20 = 12(f + -5) + f

Reorder the terms:
3(20 + f) + 20 = 12(f + -5) + f
(20 * 3 + f * 3) + 20 = 12(f + -5) + f
(60 + 3f) + 20 = 12(f + -5) + f

Reorder the terms:
60 + 20 + 3f = 12(f + -5) + f

Combine like terms: 60 + 20 = 80
80 + 3f = 12(f + -5) + f

Reorder the terms:
80 + 3f = 12(-5 + f) + f
80 + 3f = (-5 * 12 + f * 12) + f
80 + 3f = (-60 + 12f) + f

Combine like terms: 12f + f = 13f
80 + 3f = -60 + 13f

Solving
80 + 3f = -60 + 13f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-13f' to each side of the equation.
80 + 3f + -13f = -60 + 13f + -13f

Combine like terms: 3f + -13f = -10f
80 + -10f = -60 + 13f + -13f

Combine like terms: 13f + -13f = 0
80 + -10f = -60 + 0
80 + -10f = -60

Add '-80' to each side of the equation.
80 + -80 + -10f = -60 + -80

Combine like terms: 80 + -80 = 0
0 + -10f = -60 + -80
-10f = -60 + -80

Combine like terms: -60 + -80 = -140
-10f = -140

Divide each side by '-10'.
f = 14

Simplifying
f = 14

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