3(f+22)=4(f+12)

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Solution for 3(f+22)=4(f+12) equation:



3(f+22)=4(f+12)
We move all terms to the left:
3(f+22)-(4(f+12))=0
We multiply parentheses
3f-(4(f+12))+66=0
We calculate terms in parentheses: -(4(f+12)), so:
4(f+12)
We multiply parentheses
4f+48
Back to the equation:
-(4f+48)
We get rid of parentheses
3f-4f-48+66=0
We add all the numbers together, and all the variables
-1f+18=0
We move all terms containing f to the left, all other terms to the right
-f=-18
f=-18/-1
f=+18

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