3(f+4)-5=(2f-6)-4

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Solution for 3(f+4)-5=(2f-6)-4 equation: 



3(f+4)-5=(2f-6)-4

We move all terms to the left:

3(f+4)-5-((2f-6)-4)=0

We multiply parentheses

3f-((2f-6)-4)+12-5=0



We calculate terms in parentheses: -((2f-6)-4), so:

(2f-6)-4

We get rid of parentheses

2f-6-4

We add all the numbers together, and all the variables

2f-10

Back to the equation:

-(2f-10)



We add all the numbers together, and all the variables

3f-(2f-10)+7=0

We get rid of parentheses

3f-2f+10+7=0

We add all the numbers together, and all the variables

f+17=0

We move all terms containing f to the left, all other terms to the right

f=-17

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