3(f+4)=2(3f-5)

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Solution for 3(f+4)=2(3f-5) equation: 



3(f+4)=2(3f-5)

We move all terms to the left:

3(f+4)-(2(3f-5))=0

We multiply parentheses

3f-(2(3f-5))+12=0



We calculate terms in parentheses: -(2(3f-5)), so:

2(3f-5)

We multiply parentheses

6f-10

Back to the equation:

-(6f-10)



We get rid of parentheses

3f-6f+10+12=0

We add all the numbers together, and all the variables

-3f+22=0

We move all terms containing f to the left, all other terms to the right

-3f=-22

f=-22/-3

f=7+1/3

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