3(f+4)=2(3f-5)

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Solution for 3(f+4)=2(3f-5) equation:



3(f+4)=2(3f-5)
We move all terms to the left:
3(f+4)-(2(3f-5))=0
We multiply parentheses
3f-(2(3f-5))+12=0
We calculate terms in parentheses: -(2(3f-5)), so:
2(3f-5)
We multiply parentheses
6f-10
Back to the equation:
-(6f-10)
We get rid of parentheses
3f-6f+10+12=0
We add all the numbers together, and all the variables
-3f+22=0
We move all terms containing f to the left, all other terms to the right
-3f=-22
f=-22/-3
f=7+1/3

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