3(f+41)=35

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Solution for 3(f+41)=35 equation: 



3(f+41)=35

We move all terms to the left:

3(f+41)-(35)=0

We multiply parentheses

3f+123-35=0

We add all the numbers together, and all the variables

3f+88=0

We move all terms containing f to the left, all other terms to the right

3f=-88

f=-88/3

f=-29+1/3

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