3(f+5)=2(3f+12)

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Solution for 3(f+5)=2(3f+12) equation: 



3(f+5)=2(3f+12)

We move all terms to the left:

3(f+5)-(2(3f+12))=0

We multiply parentheses

3f-(2(3f+12))+15=0



We calculate terms in parentheses: -(2(3f+12)), so:

2(3f+12)

We multiply parentheses

6f+24

Back to the equation:

-(6f+24)



We get rid of parentheses

3f-6f-24+15=0

We add all the numbers together, and all the variables

-3f-9=0

We move all terms containing f to the left, all other terms to the right

-3f=9

f=9/-3

f=-3

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