3(f-10)+2(f-22)=6

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Solution for 3(f-10)+2(f-22)=6 equation: 



3(f-10)+2(f-22)=6

We move all terms to the left:

3(f-10)+2(f-22)-(6)=0

We multiply parentheses

3f+2f-30-44-6=0

We add all the numbers together, and all the variables

5f-80=0

We move all terms containing f to the left, all other terms to the right

5f=80

f=80/5

f=16

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