3(f-2)=2(f+0.5)

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Solution for 3(f-2)=2(f+0.5) equation: 



3(f-2)=2(f+0.5)

We move all terms to the left:

3(f-2)-(2(f+0.5))=0

We multiply parentheses

3f-(2(f+0.5))-6=0



We calculate terms in parentheses: -(2(f+0.5)), so:

2(f+0.5)

We multiply parentheses

2f+1

Back to the equation:

-(2f+1)



We get rid of parentheses

3f-2f-1-6=0

We add all the numbers together, and all the variables

f-7=0

We move all terms containing f to the left, all other terms to the right

f=7

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