3(f-3)+5=(f-1)

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Solution for 3(f-3)+5=(f-1) equation: 



3(f-3)+5=(f-1)

We move all terms to the left:

3(f-3)+5-((f-1))=0

We multiply parentheses

3f-((f-1))-9+5=0



We calculate terms in parentheses: -((f-1)), so:

(f-1)

We get rid of parentheses

f-1

Back to the equation:

-(f-1)



We add all the numbers together, and all the variables

3f-(f-1)-4=0

We get rid of parentheses

3f-f+1-4=0

We add all the numbers together, and all the variables

2f-3=0

We move all terms containing f to the left, all other terms to the right

2f=3

f=3/2

f=1+1/2

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