3(f-3)=5(2f+)

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Solution for 3(f-3)=5(2f+) equation:



3(f-3)=5(2f+)
We move all terms to the left:
3(f-3)-(5(2f+))=0
We add all the numbers together, and all the variables
3(f-3)-(5(+2f))=0
We multiply parentheses
3f-(5(+2f))-9=0
We calculate terms in parentheses: -(5(+2f)), so:
5(+2f)
We multiply parentheses
10f
Back to the equation:
-(10f)
We add all the numbers together, and all the variables
-7f-9=0
We move all terms containing f to the left, all other terms to the right
-7f=9
f=9/-7
f=-1+2/7

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