3(f-3)=5(2f+1)

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Solution for 3(f-3)=5(2f+1) equation: 



3(f-3)=5(2f+1)

We move all terms to the left:

3(f-3)-(5(2f+1))=0

We multiply parentheses

3f-(5(2f+1))-9=0



We calculate terms in parentheses: -(5(2f+1)), so:

5(2f+1)

We multiply parentheses

10f+5

Back to the equation:

-(10f+5)



We get rid of parentheses

3f-10f-5-9=0

We add all the numbers together, and all the variables

-7f-14=0

We move all terms containing f to the left, all other terms to the right

-7f=14

f=14/-7

f=-2

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