3(f-4)+12=2(f+1+2)

Solution for 3(f-4)+12=2(f+1+2) equation:

Simplifying
3(f + -4) + 12 = 2(f + 1 + 2)

Reorder the terms:
3(-4 + f) + 12 = 2(f + 1 + 2)
(-4 * 3 + f * 3) + 12 = 2(f + 1 + 2)
(-12 + 3f) + 12 = 2(f + 1 + 2)

Reorder the terms:
-12 + 12 + 3f = 2(f + 1 + 2)

Combine like terms: -12 + 12 = 0
0 + 3f = 2(f + 1 + 2)
3f = 2(f + 1 + 2)

Reorder the terms:
3f = 2(1 + 2 + f)

Combine like terms: 1 + 2 = 3
3f = 2(3 + f)
3f = (3 * 2 + f * 2)
3f = (6 + 2f)

Solving
3f = 6 + 2f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-2f' to each side of the equation.
3f + -2f = 6 + 2f + -2f

Combine like terms: 3f + -2f = 1f
1f = 6 + 2f + -2f

Combine like terms: 2f + -2f = 0
1f = 6 + 0
1f = 6

Divide each side by '1'.
f = 6

Simplifying
f = 6