3(f-8)+6(f-12)=12

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Solution for 3(f-8)+6(f-12)=12 equation: 



3(f-8)+6(f-12)=12

We move all terms to the left:

3(f-8)+6(f-12)-(12)=0

We multiply parentheses

3f+6f-24-72-12=0

We add all the numbers together, and all the variables

9f-108=0

We move all terms containing f to the left, all other terms to the right

9f=108

f=108/9

f=12

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