3(f-9)+10(f-11)=90

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Solution for 3(f-9)+10(f-11)=90 equation: 



3(f-9)+10(f-11)=90

We move all terms to the left:

3(f-9)+10(f-11)-(90)=0

We multiply parentheses

3f+10f-27-110-90=0

We add all the numbers together, and all the variables

13f-227=0

We move all terms containing f to the left, all other terms to the right

13f=227

f=227/13

f=17+6/13

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