3(g)+3(1)=2(5g+5)

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Solution for 3(g)+3(1)=2(5g+5) equation:



3(g)+3(1)=2(5g+5)
We move all terms to the left:
3(g)+3(1)-(2(5g+5))=0
We calculate terms in parentheses: -(2(5g+5)), so:
2(5g+5)
We multiply parentheses
10g+10
Back to the equation:
-(10g+10)
We get rid of parentheses
3g-10g-10+31=0
We add all the numbers together, and all the variables
-7g+21=0
We move all terms containing g to the left, all other terms to the right
-7g=-21
g=-21/-7
g=+3

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