3(g+1)+2(g+1)=7g-11

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Solution for 3(g+1)+2(g+1)=7g-11 equation: 



3(g+1)+2(g+1)=7g-11

We move all terms to the left:

3(g+1)+2(g+1)-(7g-11)=0

We multiply parentheses

3g+2g-(7g-11)+3+2=0

We get rid of parentheses

3g+2g-7g+11+3+2=0

We add all the numbers together, and all the variables

-2g+16=0

We move all terms containing g to the left, all other terms to the right

-2g=-16

g=-16/-2

g=+8

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