3(g+2)-4=6g-10

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Solution for 3(g+2)-4=6g-10 equation: 



3(g+2)-4=6g-10

We move all terms to the left:

3(g+2)-4-(6g-10)=0

We multiply parentheses

3g-(6g-10)+6-4=0

We get rid of parentheses

3g-6g+10+6-4=0

We add all the numbers together, and all the variables

-3g+12=0

We move all terms containing g to the left, all other terms to the right

-3g=-12

g=-12/-3

g=+4

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