3(g-7)=2(10+g)+

Solution for 3(g-7)=2(10+g)+ equation:

3(g-7)=2(10+g)+

We move all terms to the left:

3(g-7)-(2(10+g)+)=0

We add all the numbers together, and all the variables

3(g-7)-(2(g+10)+)=0

We multiply parentheses

3g-(2(g+10)+)-21=0


We calculate terms in parentheses: -(2(g+10)+), so:

2(g+10)+

We add all the numbers together, and all the variables

2(g+10)

We multiply parentheses

2g+20

Back to the equation:

-(2g+20)


We get rid of parentheses

3g-2g-20-21=0

We add all the numbers together, and all the variables

g-41=0

We move all terms containing g to the left, all other terms to the right

g=41