3(g-7)=20(10+g)

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Solution for 3(g-7)=20(10+g) equation: 



3(g-7)=20(10+g)

We move all terms to the left:

3(g-7)-(20(10+g))=0

We add all the numbers together, and all the variables

3(g-7)-(20(g+10))=0

We multiply parentheses

3g-(20(g+10))-21=0



We calculate terms in parentheses: -(20(g+10)), so:

20(g+10)

We multiply parentheses

20g+200

Back to the equation:

-(20g+200)



We get rid of parentheses

3g-20g-200-21=0

We add all the numbers together, and all the variables

-17g-221=0

We move all terms containing g to the left, all other terms to the right

-17g=221

g=221/-17

g=-13

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