3(g2+2)=(3g-2)

Solution for 3(g2+2)=(3g-2) equation:

3(g2+2)=(3g-2)

We move all terms to the left:

3(g2+2)-((3g-2))=0

We add all the numbers together, and all the variables

3(+g^2+2)-((3g-2))=0

We multiply parentheses

3g^2-((3g-2))+6=0


We calculate terms in parentheses: -((3g-2)), so:

(3g-2)

We get rid of parentheses

3g-2

Back to the equation:

-(3g-2)


We get rid of parentheses

3g^2-3g+2+6=0

We add all the numbers together, and all the variables

3g^2-3g+8=0

a = 3; b = -3; c = +8;
Δ = b2-4ac
Δ = -32-4·3·8
Δ = -87
Delta is less than zero, so there is no solution for the equation