3(h+1)+2(h+3)+4(2h-1)=109

Solution for 3(h+1)+2(h+3)+4(2h-1)=109 equation:

Simplifying
3(h + 1) + 2(h + 3) + 4(2h + -1) = 109

Reorder the terms:
3(1 + h) + 2(h + 3) + 4(2h + -1) = 109
(1 * 3 + h * 3) + 2(h + 3) + 4(2h + -1) = 109
(3 + 3h) + 2(h + 3) + 4(2h + -1) = 109

Reorder the terms:
3 + 3h + 2(3 + h) + 4(2h + -1) = 109
3 + 3h + (3 * 2 + h * 2) + 4(2h + -1) = 109
3 + 3h + (6 + 2h) + 4(2h + -1) = 109

Reorder the terms:
3 + 3h + 6 + 2h + 4(-1 + 2h) = 109
3 + 3h + 6 + 2h + (-1 * 4 + 2h * 4) = 109
3 + 3h + 6 + 2h + (-4 + 8h) = 109

Reorder the terms:
3 + 6 + -4 + 3h + 2h + 8h = 109

Combine like terms: 3 + 6 = 9
9 + -4 + 3h + 2h + 8h = 109

Combine like terms: 9 + -4 = 5
5 + 3h + 2h + 8h = 109

Combine like terms: 3h + 2h = 5h
5 + 5h + 8h = 109

Combine like terms: 5h + 8h = 13h
5 + 13h = 109

Solving
5 + 13h = 109

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 13h = 109 + -5

Combine like terms: 5 + -5 = 0
0 + 13h = 109 + -5
13h = 109 + -5

Combine like terms: 109 + -5 = 104
13h = 104

Divide each side by '13'.
h = 8

Simplifying
h = 8