3(h+1)=2(h-5)

Solution for 3(h+1)=2(h-5) equation:

Simplifying
3(h + 1) = 2(h + -5)

Reorder the terms:
3(1 + h) = 2(h + -5)
(1 * 3 + h * 3) = 2(h + -5)
(3 + 3h) = 2(h + -5)

Reorder the terms:
3 + 3h = 2(-5 + h)
3 + 3h = (-5 * 2 + h * 2)
3 + 3h = (-10 + 2h)

Solving
3 + 3h = -10 + 2h

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-2h' to each side of the equation.
3 + 3h + -2h = -10 + 2h + -2h

Combine like terms: 3h + -2h = 1h
3 + 1h = -10 + 2h + -2h

Combine like terms: 2h + -2h = 0
3 + 1h = -10 + 0
3 + 1h = -10

Add '-3' to each side of the equation.
3 + -3 + 1h = -10 + -3

Combine like terms: 3 + -3 = 0
0 + 1h = -10 + -3
1h = -10 + -3

Combine like terms: -10 + -3 = -13
1h = -13

Divide each side by '1'.
h = -13

Simplifying
h = -13