3(h+2)-4(h-10)=46

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Solution for 3(h+2)-4(h-10)=46 equation: 



3(h+2)-4(h-10)=46

We move all terms to the left:

3(h+2)-4(h-10)-(46)=0

We multiply parentheses

3h-4h+6+40-46=0

We add all the numbers together, and all the variables

-h=0

h=0/-1

h=0

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