3(h+2)=9(h-2)

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Solution for 3(h+2)=9(h-2) equation: 



3(h+2)=9(h-2)

We move all terms to the left:

3(h+2)-(9(h-2))=0

We multiply parentheses

3h-(9(h-2))+6=0



We calculate terms in parentheses: -(9(h-2)), so:

9(h-2)

We multiply parentheses

9h-18

Back to the equation:

-(9h-18)



We get rid of parentheses

3h-9h+18+6=0

We add all the numbers together, and all the variables

-6h+24=0

We move all terms containing h to the left, all other terms to the right

-6h=-24

h=-24/-6

h=+4

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