3(h-10)+4(h-18)=10

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Solution for 3(h-10)+4(h-18)=10 equation: 



3(h-10)+4(h-18)=10

We move all terms to the left:

3(h-10)+4(h-18)-(10)=0

We multiply parentheses

3h+4h-30-72-10=0

We add all the numbers together, and all the variables

7h-112=0

We move all terms containing h to the left, all other terms to the right

7h=112

h=112/7

h=16

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