3(h-10)=2(2h+5)

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Solution for 3(h-10)=2(2h+5) equation: 



3(h-10)=2(2h+5)

We move all terms to the left:

3(h-10)-(2(2h+5))=0

We multiply parentheses

3h-(2(2h+5))-30=0



We calculate terms in parentheses: -(2(2h+5)), so:

2(2h+5)

We multiply parentheses

4h+10

Back to the equation:

-(4h+10)



We get rid of parentheses

3h-4h-10-30=0

We add all the numbers together, and all the variables

-1h-40=0

We move all terms containing h to the left, all other terms to the right

-h=40

h=40/-1

h=-40

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