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3(h-10)=2(2h+5)
We move all terms to the left:
3(h-10)-(2(2h+5))=0
We multiply parentheses
3h-(2(2h+5))-30=0
We calculate terms in parentheses: -(2(2h+5)), so:We get rid of parentheses
2(2h+5)
We multiply parentheses
4h+10
Back to the equation:
-(4h+10)
3h-4h-10-30=0
We add all the numbers together, and all the variables
-1h-40=0
We move all terms containing h to the left, all other terms to the right
-h=40
h=40/-1
h=-40
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