3(h-14)+7(h-12)=14

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Solution for 3(h-14)+7(h-12)=14 equation: 



3(h-14)+7(h-12)=14

We move all terms to the left:

3(h-14)+7(h-12)-(14)=0

We multiply parentheses

3h+7h-42-84-14=0

We add all the numbers together, and all the variables

10h-140=0

We move all terms containing h to the left, all other terms to the right

10h=140

h=140/10

h=14

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