3(h-2)+1=-h+4+5h

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Solution for 3(h-2)+1=-h+4+5h equation: 



3(h-2)+1=-h+4+5h

We move all terms to the left:

3(h-2)+1-(-h+4+5h)=0

We add all the numbers together, and all the variables

3(h-2)-(4h+4)+1=0

We multiply parentheses

3h-(4h+4)-6+1=0

We get rid of parentheses

3h-4h-4-6+1=0

We add all the numbers together, and all the variables

-1h-9=0

We move all terms containing h to the left, all other terms to the right

-h=9

h=9/-1

h=-9

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