3(h-4)=1/3(24-6h)

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Solution for 3(h-4)=1/3(24-6h) equation: 



3(h-4)=1/3(24-6h)

We move all terms to the left:

3(h-4)-(1/3(24-6h))=0



Domain of the equation: 3(24-6h))!=0

h∈R



We add all the numbers together, and all the variables

3(h-4)-(1/3(-6h+24))=0

We multiply parentheses

3h-(1/3(-6h+24))-12=0

We multiply all the terms by the denominator


3h*3(-6h+24))-(1-12*3(-6h+24))=0

Wy multiply elements

9h^2(--36h(-=0

We use the square of the difference formula

9h^2(+36h(-=0

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