3(h-4)=5(h-10)+7h

Solution for 3(h-4)=5(h-10)+7h equation:

3(h-4)=5(h-10)+7h

We move all terms to the left:

3(h-4)-(5(h-10)+7h)=0

We multiply parentheses

3h-(5(h-10)+7h)-12=0


We calculate terms in parentheses: -(5(h-10)+7h), so:

5(h-10)+7h

We add all the numbers together, and all the variables

7h+5(h-10)

We multiply parentheses

7h+5h-50

We add all the numbers together, and all the variables

12h-50

Back to the equation:

-(12h-50)


We get rid of parentheses

3h-12h+50-12=0

We add all the numbers together, and all the variables

-9h+38=0

We move all terms containing h to the left, all other terms to the right

-9h=-38

h=-38/-9

h=4+2/9