3(h-6)=2(2-2h)

Solution for 3(h-6)=2(2-2h) equation:

3(h-6)=2(2-2h)

We move all terms to the left:

3(h-6)-(2(2-2h))=0

We add all the numbers together, and all the variables

3(h-6)-(2(-2h+2))=0

We multiply parentheses

3h-(2(-2h+2))-18=0


We calculate terms in parentheses: -(2(-2h+2)), so:

2(-2h+2)

We multiply parentheses

-4h+4

Back to the equation:

-(-4h+4)


We get rid of parentheses

3h+4h-4-18=0

We add all the numbers together, and all the variables

7h-22=0

We move all terms containing h to the left, all other terms to the right

7h=22

h=22/7

h=3+1/7