3(i+5)=2(3i+12)

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Solution for 3(i+5)=2(3i+12) equation: 



3(i+5)=2(3i+12)

We move all terms to the left:

3(i+5)-(2(3i+12))=0

We multiply parentheses

3i-(2(3i+12))+15=0



We calculate terms in parentheses: -(2(3i+12)), so:

2(3i+12)

We multiply parentheses

6i+24

Back to the equation:

-(6i+24)



We get rid of parentheses

3i-6i-24+15=0

We add all the numbers together, and all the variables

-3i-9=0

We move all terms containing i to the left, all other terms to the right

-3i=9

i=9/-3

i=-3

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