3(i-2)+4i+8=23

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Solution for 3(i-2)+4i+8=23 equation: 



3(i-2)+4i+8=23

We move all terms to the left:

3(i-2)+4i+8-(23)=0

We add all the numbers together, and all the variables

4i+3(i-2)-15=0

We multiply parentheses

4i+3i-6-15=0

We add all the numbers together, and all the variables

7i-21=0

We move all terms containing i to the left, all other terms to the right

7i=21

i=21/7

i=3

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